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Here is the solution for integers (represented as floating arrays, if you want to do floating point arithmetic, of course). The variable replacement_value represents whatever value you think is appropriate in the circumstances. Something like 1e-6 often works fine.

IDL> c = a / (b + replacement_value * (b EQ 0))

For floating point values, where the number zero cannot be assumed to be exactly zero, Jean Hasban suggests this variation,

IDL> c = a / (b + replacement_value * (ABS(b) LT epsilon))

where epsilon is usually taken to be something like the smallest number that can be represented on your computer, or:

IDL> epsilon = (Machar()).eps   IDL> Print, epsilon        1.19209e-007

Other users just prefer to get the error. Then, at least they know what is going on.

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